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Eureka Math Grade 3 Module 1 Lesson 6 Answer Key
Engage ny eureka math 3rd grade module 1 lesson 6 answer key.
Eureka Math Grade 3 Module 1 Answer Key
Eureka Math Grade 3 Module 1 Lesson 6 Problem Set Answer Key
Explanation: Given Rick puts 15 tennis balls into cans and each can holds 3 balls. Circled groups of 3 to show the balls in each can. Rick needs 15 ÷ 3 = 5, 5 × 3 = 15, Therefore Rick needs 5 cans.
Explanation: Given Rick uses 15 tennis balls to make 5 equal groups. Drawn circles to show 3 number of tennis balls are in each group as 15 ÷ 5 = 3, 5 × 3 = 15, Therefore, there are 3 tennis balls in each group.
b. 5 × __3____ = 15 15 ÷ 5 = __3____ The number in the blanks represents ____________3 balls in each group________.
Answer: The number in the blanks represents 3 balls in each group,
Explanation: Rick uses 15 tennis balls to make 5 equal groups, 15 ÷ 5 = 3 or 5 × 3= 15, The number in the blanks represents 3 balls in each group.
Question 4. Deena makes 21 jars of tomato sauce. She puts 7 jars in each box to sell at the market. How many boxes does Deena need? 21 ÷ 7 = __3____ ___3___ × 7 = 21 What is the meaning of the unknown factor and quotient? _________3______________
Answer: Deena needs 3 boxes,
Explanation: Given Deena makes 21 jars of tomato sauce and she puts 7 jars in each box to sell at the market. So number of boxes Deena needs are 21 ÷ 7 = 3, (3 × 7 = 21) Therefore, Deena needs 3 boxes.
Question 5. The teacher gives the equation 4 × __3__ = 12. Charlie finds the answer by writing and solving 12 ÷ 4 = __3__. Explain why Charlie’s method works.
Answer: Charlie method is 12 ÷ 4 = 3,
Explanation: Given The teacher gives the equation 4 × ____ = 12. Charlie finds the answer by writing and solving as 12 ÷ 4 = 3, because multiplication and division are closely related, given that division is the inverse operation of multiplication. When we divide, we look to separate into equal groups, while multiplication involves joining equal groups. If we divide this product by one of the factors, we get the other factor as a result. So Charlie uses division method to solve missing factor in the given equation as 3. So the equation is 4 X 3 = 12.
Eureka Math Grade 3 Module 1 Lesson 6 Exit Ticket Answer Key
Eureka Math Grade 3 Module 1 Lesson 6 Homework Answer Key
Explanation: Given Mr. Hannigan puts 12 pencils into boxes. Each box holds 4 pencils. Circled groups of 4 to show the pencils in each box as shown above, So Mr. Hannigan needs 12 ÷ 4 = 3 boxes, ( 3 x 4 = 12).
Explanation: Given Mr. Hannigan places 12 pencils into 3 equal groups, Drawn to show 4 number of pencils are in each group as 12 ÷ 3 = 4, 3 × 4 = 12, Therefore 4 pencils are there in each group.
Explanation: Used an array to model Problem 1 as 3 x 4 = 12, or 12 ÷ 4 = 3, therefore the number in the blanks represents 3 groups.
b. 3 × ___4___ = 12 12 ÷ 3 = __4____ The number in the blanks represents ___________4 pencils in each group_____________.
The number in the blanks represents 4 pencils in each group,
Explanation: Given Mr. Hannigan places 12 pencils into 3 equal groups. 12 ÷ 3 = 4 or 3 × 4= 12, The number in the blanks represents 4 pencils in each group.
Question 4. Judy washes 24 dishes. She then dries and stacks the dishes equally into 4 piles. How many dishes are in each pile? 24 ÷ 4 = ___6____ 4 × ___6_____ = 24 What is the meaning of the unknown factor and quotient? __________6 dishes are in each pile____________________
Answer: There are 6 dishes in each pile,
Explanation: Given Judy washes 24 dishes and she then dries and stacks the dishes equally into 4 piles. So number of dishes in each pile are 24 ÷ 4 = 6, or 4 × 6 = 24, The meaning of the unknown factor and quotient is 6 dishes are there in each pile.
Question 5. Nate solves the equation _____ × 5 = 15 by writing and solving 15 ÷ 5 = ____. Explain why Nate’s method works.
Answer: Nate solves the equation as 3 × 5 = 15,
Explanation: Given Nate solves the equation _____ × 5 = 15 by writing and solving as 15 ÷ 5 = 3, Nate’s method is correct because in the given equation ___ X 5 = 15 , we bring 5 to the other side it becomes as 15 ÷ 5 = 3 now we check as 3 × 5 it becomes 15 only. So Nate’s method work.
Explanation: Drawn an array to represent the equations as 3 × 5 = 15 or 15 ÷ 5 = 3 as shown in the picture above.
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Sep 28, 2024 · To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook. Engage NY Eureka Math 3rd Grade Module 3 Lesson 6 Answer Key. So teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students.
Oct 3, 2024 · Engage NY Eureka Math 3rd Grade Module 6 Lesson 6 Answer Key Eureka Math Grade 3 Module 6 Lesson 6 Pattern Sheet Answer Key. Multiply. multiply by 6 (1–5) Answer: Multiplying 6 with x Hear x= 1 to 5 Multiply 6 with 1 6 x 1=6 Multiply 6 with 2 6 x 2=12 Multiply 6 with 3 6 x 3=18 Multiply 6 with 4 6 x 4=24 Multiply 6 with 5 6 x 5=30. Eureka ...
Sep 20, 2024 · Engage NY Eureka Math 3rd Grade Module 1 Lesson 6 Answer Key. Eureka Math Grade 3 Module 1 Answer Key. Eureka Math Grade 3 Module 1 Lesson 6 Problem Set Answer Key. Question 1. Rick puts 15 tennis balls into cans. Each can holds 3 balls. Circle groups of 3 to show the balls in each can. Rick needs ____5___ cans. ___5___ × 3 = 15 15 ÷ 3 = __5 ...
Sep 18, 2017 · Grade 3. Gr3General. Gr3Mod1. Gr3Mod2. Gr3Mod3. Grade 3 Module 3. Topic A:The Properties of Multiplication and Division. Lesson 1. Lesson 2. Lesson 3. Topic B: Multiplication and Division Using Units o... Lesson 4. Lesson 5. Lesson 6. Lesson 7. Topic C: Multiplication and Division Using Units u... Lesson 8. Lesson 9. Video. Lesson PDF. Homework ...
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